Java Programming Practice Question
What will happen when the following code is compiled and run in Java 1.8? int i = 1, j = -1; switch(i) switch (i) { case 0, 1: j = 1; /* Line 4 */ case 2: j = 2; default: j = 0; } System.out.println("j = " + j);Answer options
A
j = 0
B
j = -1
C
j = 1
D
Compilation fails. One can not specify multiple case labels with commas, as in line 4. Hence compilation error.
Correct answer: Compilation fails. One can not specify multiple case labels with commas, as in line 4. Hence compilation error.
Explanation
Quick AnswerThe correct answer is Compilation fails. One can not specify multiple case labels with commas, as in line 4. Hence compilation error. because it directly addresses the core logic of Java Programming.
This question has been retained as-is due to its unique context.