Java Programming Practice Question
class TestArray { public static void main(String args[]) { int arr_sample[] = new int[2]; System.out.println(arr_sample[0]); } } What will be the result of compiling and executing the above code?Answer options
A
The program does not compile because arr_sample[0] is being read before being initialize
B
The program generates a runtime exception because arr_sample[0] is being read before being initialize
C
The program compiles and prints 0 when execute
D
The program compiles and prints 1 when execute
E
The program compiles and runs but the results are not predictable because of un-initialized memory being rea
Correct answer: The program compiles and prints 0 when execute
Explanation
Quick AnswerThe correct answer is The program compiles and prints 0 when execute because it directly addresses the core logic of Java Programming.
This question has been retained as-is due to its unique context.